Commit 67207186 authored by intrigeri's avatar intrigeri

tails-debugging-info: add support for commands that need to go through a shell

This will be needed for #17902.
parent fff3fb0f
......@@ -67,7 +67,11 @@ def main():
info = []
for _type, _args in config:
if _type == 'command':
info.append(debug_command(_args['args'][0], *_args['args'][1:]))
if 'shell' in _args:
shell = _args['shell']
shell = False
info.append(debug_command(args=_args['args'], shell=shell))
elif _type == 'directory':
info.append(debug_directory(_args['user'], _args['path']))
......@@ -76,15 +80,18 @@ def main():
print(json.dumps(info, indent=4))
def debug_command(command, *args):
def debug_command(args: list, shell=False):
"""Return the command and it's standard output as dict.
>>> debug_command('echo', 'foo')
>>> debug_command(['echo', 'foo'])
{...'key': 'echo foo'...}
command_output = subprocess.check_output([command, *args])
if shell:
command_output = subprocess.check_output(' '.join(args), shell=True)
command_output = subprocess.check_output(args)
command_output = command_output.decode('UTF-8').strip().split('\n')
return {'key': '{}'.format(' '.join((command,) + args)), 'content': command_output}
return {'key': '{}'.format(' '.join(args)), 'content': command_output}
def debug_file(user, filename):
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